Marleyjones 1 Posted December 11, 2016 Share Posted December 11, 2016 [E] 23:35:45 - Compilator Error : c:\Users\Adam\AppData\Local\Temp\i0mip0er.0.cs(21,61) : error CS1061: 'wManager.Wow.ObjectManager.WoWLocalPlayer' does not contain a definition for 'KnowsSpell' and no extension method 'KnowsSpell' accepting a first argument of type 'wManager.Wow.ObjectManager.WoWLocalPlayer' could be found (are you missing a using directive or an assembly reference?) [D] 23:35:47 - [Quester] If[10] (ObjectManager.Me.Level == 6 && ObjectManager.Me.KnowsSpell(6673)) | Result: False Under the Quests order editor in the Easy Quests Editor I'm trying to do a check to see if a player is a certain level and knows a spell using the Action type "If" What I have is this ObjectManager.Me.Level == 6 && ObjectManager.Me.KnowsSpell(6673) If i run it with just ObjectManager.Me.Level == 6 It works perfectly and can read that I am level 6 I'm an amateur when it comes to code and I've tried a hundred different things some examples like ObjectManager.Me.KnowsSpell(6673) ObjectManager.Me.Knows.Spell(6673) ObjectManager.Me.KnowSpell(6673) ObjectManager.Me.Knows.Spell(6673) ObjectManager.KnowsSpell(6673) Thank you so much to anyone that can help me!!! Edit: Also 6673 is the spell id for level 1 Battle Shout in WotLK 3.3.5 and I would also deeply appreciate if anyone has a link to some documentation on what I can use with ObjectManager Link to comment Share on other sites More sharing options...
Droidz 2734 Posted December 11, 2016 Share Posted December 11, 2016 Hello, use wManager.Wow.Helpers.SpellManager.KnowSpell(1234) or wManager.Wow.Helpers.SpellManager.KnowSpell("Spell Name in english") M4k5P0w3r 1 Link to comment Share on other sites More sharing options...
Marleyjones 1 Posted December 11, 2016 Author Share Posted December 11, 2016 Thank you so much! Link to comment Share on other sites More sharing options...
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